Posted by me on Friday, December 9, 2011 at 5:13pm.
Not knowing the center of gravity, lets look at energy.
Assume the distance from the piviot point to the center of mass is r.
Then the distance the mass fell is 2r, and the PE lost is 2rmg.the KE at the bottom is 1/2 m v^2, and they are equal
1/2 m v^2=2rmg
r= 1/4 v^2/g
so, period of pendulum= 2PI sqrt(r/g)
and frequncey is 1/Period
Is the formula r = (1/4)(v^2/g)? or (1/4 v^2)/g ?
period= 2PI sqrt (1/4 v^2/g^2)=2PI v/2g=PI v/g
frequency= 1/period= g/(PIv)
check that.
I am just confused on the way some of these are written out like in the period equation you just gave, is pi multiplied by v and then divided by g or is the whole quantity given by v/g multiplied by pi?
period= 2PI * sqrt(v/g)
So the first formula period=2pi*sqrt(r/g) is incorrect? I am just confused I am sorry
sorry about that, it is r/g, I am trying to clear this board too quickly.
So is the formula for r: r = (1/4)(v^2/g)? or (1/4 v^2)/g ? sorry I am asking so much
There is no difference.
a/b * c/d= ac/bd= ac/b * 1/d
1/4 v^2/g= 1/4 v^2/g= 1/(4g) * v^2
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