Posted by Amy on Friday, December 9, 2011 at 4:51pm.
What woman? It's just a math problem, like others in your book...
You have (x-4)(x+3)/(x+1)
domain is all reals except where denominator is zero. That is all reals except x = -1
zeros at x = 4 and -3 because that's where the numerator is zero and the denominator is not zero
no horizontal asymptotes, since the numerator has higher degree than the denominator. As x gets large, the fraction is just x^2/x = x
So, oblique asymptote is y=x
The graph intersects it at (-6,-6)
A little interval chart will show that
y<0 for x in (-oo,-3)U(-1,4)
y>0 for x in (-3,-1)U(4,oo)
At the end you say you can graph it. Well! In that case, what's the problem? The graph shows all the answers to the questions.
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