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April 1, 2015

April 1, 2015

Posted by **Amy** on Friday, December 9, 2011 at 4:51pm.

I know the division brings it to x -2 + -10/x + 1

but these are the steps I have to follow

1. factor the numerator and denominator and find its domain.

( I know 0 is not in domain)

2. write in lowest ermas as p(x)/ q(x) and find the real zeros of the numerator that is find the ral solutions of the equation p(x) = 0

3. find the ral zeros of the denominator that is find the real solution of q(x) = 0

4. locate horizontal or oblique asymptotes determine points at which the graph intersects these asymptotes

5. using the real zeros of the numerator and denominator divide the x axis into intervals and determine where the graph is above the x axis and where below the x axis

6. analyze the behavior of the graph near each asymptote and indicate behavior on the graph.

7. graph ( this I can do )

Help me! This woman is impossible!!!!!

- pre cal -
**Steve**, Friday, December 9, 2011 at 5:37pmWhat woman? It's just a math problem, like others in your book...

You have (x-4)(x+3)/(x+1)

domain is all reals except where denominator is zero. That is all reals except x = -1

zeros at x = 4 and -3 because that's where the numerator is zero and the denominator is not zero

no horizontal asymptotes, since the numerator has higher degree than the denominator. As x gets large, the fraction is just x^2/x = x

So, oblique asymptote is y=x

The graph intersects it at (-6,-6)

A little interval chart will show that

y<0 for x in (-oo,-3)U(-1,4)

y>0 for x in (-3,-1)U(4,oo)

At the end you say you can graph it. Well! In that case, what's the problem? The graph shows all the answers to the questions.

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