Friday

August 22, 2014

August 22, 2014

Posted by **Alissa** on Friday, December 9, 2011 at 4:42pm.

degree: 6

Zeros: -8 + 11x(can't put this sign in looks like ii with slash over)i, -7 + 17i, 16 - isqrt 2

- algebra -
**Steve**, Friday, December 9, 2011 at 5:27pmYou know that since the roots come in conjugate pairs, there will be

-7 + 17i and -7 -17i

16 - isqrt2 and 16 + isqrt2

so the factors will be

(x^2 - 14x + 338) that's (x^2 -2*7x + 17^2 + 7^2)

(x^2 - 32x + 258) that's (x^2 - 2*16x + 16^2 + sqrt2^2)

and the other pair you can figure out. I can't tell what you mean.

- algebra - typo -
**Steve**, Friday, December 9, 2011 at 5:28pmHmm. I think that's +14x in the 1st case -(2*-7)

**Related Questions**

calculus--please help!! - I have two questions that I don't understand and need ...

Algebra - Information is given about a polynomial f(x) whose coefficients are ...

Math - Use the given information about a polynomial whose coefficients are real...

college algebra--need help please!! - information is given about a polynomial f(...

college algebra--need help please!! - information is given about a polynomial f(...

college algebra--need help please!! - information is given about a polynomial f(...

Pre-calculus - Sorry i wrote the last question wrong, it was suppose to be ...

pre calculus - use given info about a polynomial whose coefficients are real ...

pre-calculus - information is given about the polynomial f(x) whose coefficients...

calculus - information is given about a polynomial f(x) whose coeffiecients are ...