Posted by **Alissa** on Friday, December 9, 2011 at 4:42pm.

Use the given information about a polynomial whose coefficients are real numbers to find the remaining zeros.

degree: 6

Zeros: -8 + 11x(can't put this sign in looks like ii with slash over)i, -7 + 17i, 16 - isqrt 2

- algebra -
**Steve**, Friday, December 9, 2011 at 5:27pm
You know that since the roots come in conjugate pairs, there will be

-7 + 17i and -7 -17i

16 - isqrt2 and 16 + isqrt2

so the factors will be

(x^2 - 14x + 338) that's (x^2 -2*7x + 17^2 + 7^2)

(x^2 - 32x + 258) that's (x^2 - 2*16x + 16^2 + sqrt2^2)

and the other pair you can figure out. I can't tell what you mean.

- algebra - typo -
**Steve**, Friday, December 9, 2011 at 5:28pm
Hmm. I think that's +14x in the 1st case -(2*-7)

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