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precalulus

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use the intermediate value theorem to show that f(x) has a zero in the given interval. f(x) = -x^5 -2x^4 + 5x^3 + 4; [-0.9, -0.8]
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  • precalulus -

    f(-.9) = -.367
    f(-.8) = +.948

    since f is continuous, it must assume all values between -.367 and +.948 on the interval [-.9,-.8].

    That includes f(x) = 0.

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