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Algebra

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Algebraically at what temp is Celsius 1/4 that of Fahrenheit??

ie C = 1/4 F

  • Algebra - ,

    TF = Fahrenheit temperature

    TC = Celsius temperature



    TF = ( 9 / 5 ) * TC + 32

    TF = ( 9 / 5) * ( 1 / 4 ) + 32

    TF = ( 9 / 20 ) + 32

    TF = 9 / 20 + 640 / 20

    TF = 649 / 20

    TF = 32.45


    ( 1 / 4 ) ° C = 32.45 ° F

  • Algebra - ,

    Hmmm. I interpreted it to mean
    Find the temperature where C temperature is 1/4 the F

    C = 1/4 (9/5 C + 32)
    4C = 9/5 C + 32
    20C = 9C + 160
    11C = 160
    C = 14.545

    F = 9/5 * 14.54 + 32 = 58.18

    58.18 = 4*14.545

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