Posted by **Jill** on Friday, December 9, 2011 at 12:38pm.

The question says "Given that cos(theta)=(-7/25) and sin(theta)>0, calculate the exact values of tan(theta) and csc(theta).

We start out by drawing a triangle.

25 is on the side of the hypotenuse and -7 is on the adjacent side, because cos is adjacent over hypotenuse.

Somehow he gets to this halfway through: 225-49=176.

I can understand where he got the 49.

Probably from (-7)^2

I thought you had to use the equation

a^2+b^2=c^2 or

y^2+x^2=r^2

So it would be y^2 +(-7)^2=25^2

(-7)^2 is 49. Subtract this from 25^2, so we can get y^2 by itself.

Would that be going the right way?

I'm mainly just confused about how he got the 225?

- Confuses how my teacher got this? -
**Jill**, Friday, December 9, 2011 at 12:41pm
He ends up with the answers:

tan(theta)= (-square root of 176)/7 and

csc(theta)= (25 x square root of 176)/176

- Confuses how my teacher got this? -
**Steve**, Friday, December 9, 2011 at 12:49pm
Looks like either the hypotenuse is 15, so 15^2 = 225

or, he made a mistake and it should have been 625, rather than 225. I think this is the case, because then you have a 7-24-25 triangle.

- Confuses how my teacher got this? -
**Jill**, Friday, December 9, 2011 at 12:53pm
I think its the second one, but how did you get 625?

- Confuses how my teacher got this? -
**Steve**, Friday, December 9, 2011 at 1:09pm
He started out saying that cos = 7/25. That means that if the other leg i y, then

7^2 + y^2 = 25^2 = 625

y = 24

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