Posted by Billy NEED HELP on Friday, December 9, 2011 at 11:41am.
okay so i made arctan(-4/3) = x
so im solving for sin(x)
and x= arctan(-4/3)
so then tanx = -4/3
and now im stuck i don't know what to do after that
PRE-CALC - Damon, Friday, December 9, 2011 at 11:52am
Draw the right triangle (3,4,5)
3^2+4^2 = 9+16 = 25 = 5^2
angle A = atan(4/3)
sin A = 4/5
now look for quadrant
tan = -4/3 in quadrant 2 and in quadrant 4
in quadrant 2 sin A = 4/5
in quadrant 4 sin A = -4/5
PRE-CALC - Steve, Friday, December 9, 2011 at 11:52am
just draw the triangle
tan = y/x
sin = y/h
h = 5 (3-4-5 triangle!)
principal value of arctan(-4/3) is in QIV.
sin = -4/5
Answer This Question
More Related Questions
- Trigonometry - I need help with I just can't seem to get anywhere. this is as ...
- precal - The values of x that are solutions to the equation cos^(2)x=sin2x in ...
- calc - also: integral of tan^(-1)y dy how is integration of parts used in that? ...
- calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...
- Math - Arrange these in order from least to greatest: arctan(-sqrt3), arctan 0, ...
- Calculus - Note that pi lim arctan(x ) = ---- x -> +oo 2 Now evaluate / pi \ ...
- calculus - Now we prove Machin's formula using the tangent addition formula: tan...
- check my arctan please - arctan(1/12)= 4.763 rounded to the nearest tenth degree...
- Calculus prince@18 - let the function h(x)= (integrand symbol from 2 to x^2)...
- calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...