Thursday

July 24, 2014

July 24, 2014

Posted by **Billy NEED HELP** on Friday, December 9, 2011 at 11:41am.

okay so i made arctan(-4/3) = x

so im solving for sin(x)

and x= arctan(-4/3)

so then tanx = -4/3

and now im stuck i dont know what to do after that

- PRE-CALC -
**Damon**, Friday, December 9, 2011 at 11:52amDraw the right triangle (3,4,5)

3^2+4^2 = 9+16 = 25 = 5^2

angle A = atan(4/3)

sin A = 4/5

now look for quadrant

tan = -4/3 in quadrant 2 and in quadrant 4

in quadrant 2 sin A = 4/5

in quadrant 4 sin A = -4/5

- PRE-CALC -
**Steve**, Friday, December 9, 2011 at 11:52amjust draw the triangle

tan = y/x

sin = y/h

h = 5 (3-4-5 triangle!)

principal value of arctan(-4/3) is in QIV.

sin = -4/5

**Related Questions**

Trigonometry - I need help with I just can't seem to get anywhere. this is as ...

precal - The values of x that are solutions to the equation cos^(2)x=sin2x in ...

calc - also: integral of tan^(-1)y dy how is integration of parts used in that? ...

calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...

Math - Arrange these in order from least to greatest: arctan(-sqrt3), arctan 0, ...

Calculus - Note that pi lim arctan(x ) = ---- x -> +oo 2 Now evaluate / pi \ ...

calculus - Now we prove Machin's formula using the tangent addition formula: tan...

check my arctan please - arctan(1/12)= 4.763 rounded to the nearest tenth degree...

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...