Posted by Jill on Friday, December 9, 2011 at 11:30am.
sec Ų = √6
so cosŲ = 1/√6
sketch a triangle with hypotenuse √6, adjacent = 1, let the opposite be y
1^2 + y^2 = √6^2
y^2 = 5
y = √5
then sinŲ = √5/√6
cotŲ = 1/√5
Could you tell me why you squared those numbers? Is there a formula?
If I was doing sin instead, would 1^2 +y^2=√6^2 be in a different order?
Also how did you get the 5? Isn't the square of 6 to the second power just 6?
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