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November 27, 2014

November 27, 2014

Posted by **Jill** on Friday, December 9, 2011 at 11:30am.

Thank you so much!

- Pre-calc PLEASE HELP! -
**Reiny**, Friday, December 9, 2011 at 11:35amsec Ų = √6

so cosŲ = 1/√6

sketch a triangle with hypotenuse √6, adjacent = 1, let the opposite be y

1^2 + y^2 = √6^2

y^2 = 5

y = √5

then sinŲ = √5/√6

cotŲ = 1/√5

- Pre-calc PLEASE HELP! -
**Jill**, Friday, December 9, 2011 at 11:53amCould you tell me why you squared those numbers? Is there a formula?

If I was doing sin instead, would 1^2 +y^2=√6^2 be in a different order?

Also how did you get the 5? Isn't the square of 6 to the second power just 6?

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