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Posted by on Friday, December 9, 2011 at 9:00am.

The wheel of a car has a radius of 0.390 m. The engine of the car applies a torque of 466 N·m to this wheel, which does not slip against the road surface. Since the wheel does not slip, the road must be applying a force of static friction to the wheel that produces a countertorque. Moreover, the car has a constant velocity, so this countertorque balances the applied torque. What is the magnitude of the static frictional force?

  • physics - , Friday, December 9, 2011 at 9:22am

    466-fricton*radius=momentinertia*acceleration

    but acceleration is zero, so
    466=friction*radius.

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