Friday

March 6, 2015

March 6, 2015

Posted by **Anonymous** on Friday, December 9, 2011 at 4:31am.

- calculus -
**Damon**, Friday, December 9, 2011 at 5:32amdisplacement = integral v dt

= -t^3/3 + 2 t^2 - 3 t

from -2 to +6

do the arithmetic

distance traveled

that means always use absolute value of any part of the integral

when is velocity negative and when is it positive?

0 = t^2 - 4 t + 3

0 = (t-3)(t-1)

velocity 0 at t = 1 and t = 3

so:

take absolute value of integral from

-2 to + 1

add to absolute value of integral from +1 to +3

add to absolute value of integral from +3 to + 6

- calculus -
**Anonymous**, Friday, December 9, 2011 at 1:15pmthank you

**Answer this Question**

**Related Questions**

Calculus (math) - The velocity function (in meters per second) for a particle ...

math - The velocity function (in meters per second) for a particle moving along ...

math - The velocity function is v(t) = t^2 - 6 t + 8 for a particle moving along...

Math: Calculus - The velocity function is v(t)= t^2-5t+ 4 for a particle moving ...

Calculus - The velocity function is v(t)=t^2-5t+6 for a particle moving along a ...

calculus - Find the total distance traveled by the particle moving along a ...

calculus - 5. A particle moves along the y – axis with velocity given by v(t)=...

Calculus - A particle moves with a fixed acceleration of 3 m/s^2. If its initial...

Calculus - A particle moves in a straight line with velocity t^-2 - 1/9 ft/s. ...

calculus - The velocity of a particle moving along the t-axis is given by f(t)=2...