Posted by bob on Thursday, December 8, 2011 at 10:18pm.
find all solutions on 0 is greater than or equal to theta < 2pi
cos theta= 2sqrt3/3
4-1/2sin theta= (-16+sqrt3)/4
3(sqrt3)= -3cot theta
- math - Steve, Thursday, December 8, 2011 at 10:38pm
2√3/3 = 1.15
cosθ is never greater than 1.
If you mean 4-(1/2)sinθ= (-16+√3)/4
sinθ = 4 - √3/4
sorry, sinθ is never greater than 1.
If you mean 4-(1/2sinθ) = (-16+√3)/4
sinθ = 2/(32-√3) = .066
θ = 3.78°
cotθ = -√3
θ = 30°
sinθ = 1/2
θ = 30°
I'll let you figure out the other angles less than 2pi
- math - joe, Thursday, December 8, 2011 at 11:04pm
yeah im lost i have no idea what i did
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