Posted by **bob** on Thursday, December 8, 2011 at 10:18pm.

find all solutions on 0 is greater than or equal to theta < 2pi

cos theta= 2sqrt3/3

4-1/2sin theta= (-16+sqrt3)/4

3(sqrt3)= -3cot theta

-2=-1-2sin theta

- math -
**Steve**, Thursday, December 8, 2011 at 10:38pm
2√3/3 = 1.15

cosθ is never greater than 1.

_____________________

If you mean 4-(1/2)sinθ= (-16+√3)/4

sinθ = 4 - √3/4

sorry, sinθ is never greater than 1.

If you mean 4-(1/2sinθ) = (-16+√3)/4

sinθ = 2/(32-√3) = .066

θ = 3.78°

_________________

cotθ = -√3

θ = 30°

__________________

sinθ = 1/2

θ = 30°

I'll let you figure out the other angles less than 2pi

- math -
**joe**, Thursday, December 8, 2011 at 11:04pm
yeah im lost i have no idea what i did

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