Posted by **Anonymous** on Thursday, December 8, 2011 at 9:49pm.

In circle O, diameter RS has endpoints R(3a,2b-1) and S(a-6,4b+5). Find the coordinates of point O in terms of a and b. Express your answer in simplest form.

- Geometry -
**Steve**, Thursday, December 8, 2011 at 11:06pm
we know that the end points of a diameter have radially symmetric coordinates. so,

3a = -(a-6)

3a = -a + 6

4a = 6

a = 3/2

2b-1 = -(4b+5)

2b-1 = -4b-5

6b = -4

b = -2/3

R = (9/2,-7/3)

S = (-9/2,7/3)

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