Geometry
posted by Anonymous on .
In circle O, diameter RS has endpoints R(3a,2b1) and S(a6,4b+5). Find the coordinates of point O in terms of a and b. Express your answer in simplest form.

we know that the end points of a diameter have radially symmetric coordinates. so,
3a = (a6)
3a = a + 6
4a = 6
a = 3/2
2b1 = (4b+5)
2b1 = 4b5
6b = 4
b = 2/3
R = (9/2,7/3)
S = (9/2,7/3)