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September 1, 2014

September 1, 2014

Posted by **Anonymous** on Thursday, December 8, 2011 at 7:57pm.

- trig -
**Reiny**, Thursday, December 8, 2011 at 10:24pmsecØ sinØ cotØ cscØ

= (1/cosØ)(sinØ)(cosØ/sinØ)(1/sinØ)

= 1/sinØ = cscØ

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