Posted by Rock on Thursday, December 8, 2011 at 7:37pm.
If you can express the amount as
y = a*2^(-t/n)
then the half-life is n years. That is, as t increases by n, the amount is multiplied by 1/2
ae^-.0856t = a*2^(-t/n)
divide by a and take logs
-.0856t = -t/n ln 2
divide by t
.0856 = ln2/n
n = ln2/.0856 = .6931/.0856 = 8.1
So, the half-life is 8.1 days
check: wikipedia says the half-life is 8.02 days
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