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November 24, 2014

November 24, 2014

Posted by **Rock** on Thursday, December 8, 2011 at 7:37pm.

- Alg2 -
**Steve**, Friday, December 9, 2011 at 10:27amIf you can express the amount as

y = a*2^(-t/n)

then the half-life is n years. That is, as t increases by n, the amount is multiplied by 1/2

ae^-.0856t = a*2^(-t/n)

divide by a and take logs

-.0856t = -t/n ln 2

divide by t

.0856 = ln2/n

n = ln2/.0856 = .6931/.0856 = 8.1

So, the half-life is 8.1 days

check: wikipedia says the half-life is 8.02 days

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