A 0.15 kg ball of dough is thrown straight up into the air with an initial speed of 5.7 m/s.

a.)Find the momentum of the ball of dough at its maximum height.
b.) Find the momentum of the ball of dough halfway to its maximum height on the way up.

a)theres 0 velocity so momentum is 0

i don't know answer please help me.

To find the momentum of the ball of dough at its maximum height and halfway to its maximum height on the way up, we'll need to understand the concept of momentum and the laws of motion.

Momentum (p) is defined as the product of an object's mass (m) and its velocity (v):

p = m * v

a) To find the momentum of the ball of dough at its maximum height, we need to determine its velocity at that point. When the ball reaches its maximum height, its velocity becomes 0 m/s. Since momentum is the product of mass and velocity, the momentum of the ball at its maximum height will be:

p_max_height = m * v_max_height
= 0.15 kg * 0 m/s
= 0 kg·m/s

So, the momentum of the ball of dough at its maximum height is 0 kg·m/s.

b) To find the momentum of the ball of dough halfway to its maximum height on the way up, we need to determine its velocity at that point. Since the ball is thrown straight up with an initial speed of 5.7 m/s, it will slow down due to the gravitational force acting on it until it reaches its maximum height. Therefore, halfway to its maximum height, the velocity will be half of the initial velocity.

v_halfway = 5.7 m/s / 2
= 2.85 m/s

Now, we can calculate the momentum at this halfway point:

p_halfway = m * v_halfway
= 0.15 kg * 2.85 m/s
= 0.42825 kg·m/s

Therefore, the momentum of the ball of dough halfway to its maximum height on the way up is approximately 0.42825 kg·m/s.