5. Compound A has a MW of 283. 0.423g of Compound A is dissolved in 13.5mL of water and 1mL of the solution added to 5mL of water to produce “solution A”. What is the concentration of Compound A in “solution A”?

You should specify the units of concn. g/L, g/mL, M, etc.

If you want molarity, then
0.423/283.0 = moles.
moles/0.135L = M of the original.
M x 1mL/5mL = new M.

To calculate the concentration of Compound A in "solution A," we need to know the amount of Compound A that was added to the 1mL solution.

1. We start by finding the amount (in grams) of Compound A that was dissolved in 13.5mL of water:
Mass of Compound A = 0.423g

2. Now, we need to find the amount of Compound A in 1mL of the solution. To do this, we divide the mass of Compound A by the volume of the solution it was dissolved in:
Amount of Compound A in 13.5mL = 0.423g
Amount of Compound A in 1mL = Amount of Compound A in 13.5mL / 13.5mL * 1mL = 0.423g / 13.5 = 0.03133g

3. Next, we need to find the concentration of Compound A in "solution A." To do this, we divide the amount of Compound A in 1mL by the volume of "solution A":
Volume of "solution A" = 5mL
Concentration of Compound A in "solution A" = Amount of Compound A in 1mL / Volume of "solution A" = 0.03133g / 5mL = 0.00627g/mL or 6.27 mg/mL

Therefore, the concentration of Compound A in "solution A" is 6.27 mg/mL.