4. Compound B is provided as a solution and has a specific gravity of 0.65 (Specific gravity is the weight in grams per mL of solution) and is known to be 90% pure (each gram of compound B solution only contains 90% Compound B and 10% of degradation products). 4.5 mL of Compound B is diluted with 55.5mL of water. What is the concentration of this solution?

What units?

Specific gravity 0.65 is
0.65 g/mL. How much will 1000 mL weigh. It will be 0.65 g/mL x 1000 = 650 g.
How much of that is compound B? only 90%; therefore, 650 x 0.90 = 585 g B/L soln.
Then you take 4.5 mL and dilute with 55.5, which IF you assume 4.5mL + 55.5 = 60 mL (it may not be that volume you know) so the solution is now 585 g/L x (4.5/60) = ? g/L

Well, let's break it down a bit. We have 4.5 mL of Compound B, which is known to be 90% pure. So, we can calculate that 4.5 mL * 0.9 = 4.05 mL of pure Compound B.

Next, we add 55.5 mL of water to this solution, giving us a total volume of 60 mL.

To find the concentration, we divide the mass of Compound B by the total volume of the solution. However, we need to consider the specific gravity. Since specific gravity is the weight in grams per mL of solution, we can calculate the weight of the Compound B solution using specific gravity.

Considering that the specific gravity is 0.65, we can calculate the weight of 60 mL of the solution:
60 mL * 0.65 g/mL = 39 g

Now, let's calculate the concentration:
Concentration = Mass of Compound B / Total volume of the solution

Since we have 4.05 mL of pure Compound B, we need to convert it to grams:
4.05 mL * 0.65 g/mL = 2.63 g

Concentration = 2.63 g / 39 g = 0.0674 or 6.74% concentration

So, the concentration of the solution is approximately 6.74%. Which means you have 93.26% water and 6.74% Compound B. It's like finding a few drops of clown juice in a big bucket of water!

To find the concentration of the solution, we need to calculate the amount of Compound B present in the final solution after dilution.

1. Calculate the amount of Compound B in the initial solution:
- Specific gravity = 0.65 g/mL
- Volume of initial solution = 4.5 mL
- Therefore, the weight of the initial solution = 0.65 g/mL × 4.5 mL = 2.925 g

Now, as the solution is 90% pure Compound B and 10% degradation products, we can calculate the amount of Compound B in the initial solution:
- Amount of Compound B = 0.90 × 2.925 g = 2.6325 g

2. Calculate the total volume of the final solution:
- Volume of Compound B solution = 4.5 mL
- Volume of water added = 55.5 mL
- Total volume of the final solution = 4.5 mL + 55.5 mL = 60 mL

3. Calculate the concentration of the final solution:
- Concentration = Amount of Compound B / Total volume of solution
- Concentration = 2.6325 g / 60 mL
- Since specific gravity is the weight in grams per mL, we have to convert mL to grams to match the units:
1 mL = 1 gram
- Concentration = 2.6325 g / 60 g
- Concentration ≈ 0.0439 g/mL

So, the concentration of the final solution is approximately 0.0439 g/mL.

To determine the concentration of the solution, we need to calculate the amount of Compound B in grams and divide it by the total volume of the solution.

First, let's calculate the weight of Compound B in 4.5 mL of the solution:
Weight of Compound B = Volume of Compound B × Specific gravity × % purity
Weight of Compound B = 4.5 mL × 0.65 g/mL × 90%
Weight of Compound B = 2.925 grams

Next, let's calculate the total volume of the solution after dilution:
Total volume of solution = Volume of Compound B + Volume of water
Total volume of solution = 4.5 mL + 55.5 mL
Total volume of solution = 60 mL

Finally, let's calculate the concentration of the solution:
Concentration of solution = Weight of Compound B / Total volume of solution
Concentration of solution = 2.925 grams / 60 mL

To convert the units from grams per milliliter (g/mL) to grams per liter (g/L), we multiply the concentration by 1000:
Concentration of solution = (2.925 grams / 60 mL) × 1000 mL/L
Concentration of solution = 48.75 g/L

Therefore, the concentration of the solution is 48.75 grams per liter (g/L).