Posted by Joe on Thursday, December 8, 2011 at 5:19pm.
Take 1 L of solution. That will have a mass of 1000 x 1.20 g/mL = 1200 grams.
That will contain 8.20 moles NaOH or 8.20 x 40 = 328 g NaOH.
So the solution has 328 g NaOH and 1200-328 = 872 g H2O.
moles NaOH = 8.20
moles H2O = 872/molar mass H2O
XNaOH = moles NaOH/total moles.
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