posted by Minx on .
Reposting with correct information..Carbon tetrachloride (CCl4) and benzene (C6H6) form ideal solutions. Consider an equimolar solution of CCl4 and C6H6 at 25°C. The vapor above this solutionis collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor.
C6H6 (l) 124.50 kJ/mol
C6H6 (g) 129.66 kJ/mol
CCl4 (l) -65.21 kJ/mol
CCl4 (g) -60.59 kJ/mol
Delta G = -RTLNK
For c6h6 (l) to c6h6 (g) equilibrium, delta G = 129.66-124.50 = 5.16 kJ/Mol
Plug this value into the equation above and solve for the value of K, which is simply the ratio of product to reactant.
Repeat this calculation for ccl4.