Posted by **anon** on Thursday, December 8, 2011 at 4:51pm.

solve the following equation in the real number system

3x^3 - 20x^2 + 29x +12 = 0

Ok I thought I knew how to do this but I guess I don't. Help me! Please!

- college alegebra -
**Steve**, Thursday, December 8, 2011 at 5:04pm
A general cubic is hard to solve. So, expect an easy root first. Any rational root of the form a/b will be such that a divides 12 and b divides 3

A little synthetic division will show that

3x^3 - 20x^2 + 29x +12

= (x-3)(3x^2 - 11x - 4)

= (x-3)(x-4)(3x+1)

SO, knowing the factors, you should have no trouble finding the roots . . .

- college alegebra -
**anon**, Thursday, December 8, 2011 at 5:16pm
Thank you that helps a lot!

## Answer This Question

## Related Questions

- Math - factor each expression completely. if possible. Just checkin the * Ones 1...
- college algebra - Solve the following equation in the real number system. Please...
- Math - Real number system - Solve the following equation in the real number ...
- college algebra - how to solve equation in the real number system, x^4 +12x^3 +...
- college algebra - hw to solve equation in the real number system, x^4 +12x^3 +...
- college algebra--need help please!! - solve the equation in the real number ...
- alegebra - solve the sytem of equation by graphing. Then classify the system as ...
- Pre-algebra - Solve. 29x – 2(9x – 0.455) = 10x + 0.525 Give us you thinking on ...
- pre calculus - Ok not sure if it's just me with a block solve the following ...
- College Algebra - Solve the following equation in the complex number system x^4+...

More Related Questions