Posted by **anon** on Thursday, December 8, 2011 at 4:51pm.

solve the following equation in the real number system

3x^3 - 20x^2 + 29x +12 = 0

Ok I thought I knew how to do this but I guess I don't. Help me! Please!

- college alegebra -
**Steve**, Thursday, December 8, 2011 at 5:04pm
A general cubic is hard to solve. So, expect an easy root first. Any rational root of the form a/b will be such that a divides 12 and b divides 3

A little synthetic division will show that

3x^3 - 20x^2 + 29x +12

= (x-3)(3x^2 - 11x - 4)

= (x-3)(x-4)(3x+1)

SO, knowing the factors, you should have no trouble finding the roots . . .

- college alegebra -
**anon**, Thursday, December 8, 2011 at 5:16pm
Thank you that helps a lot!

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