Posted by Jane on Thursday, December 8, 2011 at 1:34pm.
A little investigation will lead you to the formula that if a hole of radius r is drilled through a sphere of radius R, the remaining volume is just 4pi/3 (R^2 - r^2)^(3/2)
In this case, that would be 4pi/3 * 3√3 = 4√3 pi
__________________________
You might also look up the napkin ring problem, where it is shown that if a hole of length h is drilled through a sphere, the remaining volume is independent of the radius of the sphere!
In this case, h/2 = R^2 - r^2 = √3, so h = 2√3
The remaining volume is pi/6 h^3 = pi/6 * 24√3 = 4√3 pi
thanks!
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