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April 18, 2014

April 18, 2014

Posted by **Dorrito** on Thursday, December 8, 2011 at 2:35am.

Answer is 8.4x10^2 but I need to see the work involved in how to solve the problem

- Physics -
**drwls**, Thursday, December 8, 2011 at 2:45amheat added = Qin = M*C*(delta T)

You must have seen that equation before. It is how specific heat is defined. Solving for C,

C = Qin/(M*C) = 2100J/(0.100 kg*25C)

= 840 J/(kg*C)

"delta T" is the increase in temerature.

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