Posted by **-Untamed-** on Wednesday, December 7, 2011 at 9:50pm.

The quadratic function f(x) = x^2 is transformed to g(x) = -2/3(x+3)^2 + 6 The point (6,36) on the graph of f is transformed to which point on the graph of g?

Could someone please show me how to solve this:\

- Math -
**Steve**, Thursday, December 8, 2011 at 10:37am
shift x left 3 (reduce x by three, since g(x+3) = f(x))

scale y by -2/3

shift y up by 6

(3,36*(-2/3)+6) = (3,-24+6) = (3,-18)

check:

g(3) = -2/3 * (3+3)^2 + 6 = -18

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