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April 16, 2014

April 16, 2014

Posted by **Anonymous** on Wednesday, December 7, 2011 at 8:35pm.

- geometry -
**Reiny**, Wednesday, December 7, 2011 at 8:49pmLet the acceleration (really deceleration) be a

so v = at + c

when t=0 , v = 30

30 = 0 + c, --> c=30

so v = at + 30

when t=2, v = 16

16 = 2a + 30

2a = -14

a = -7

v = -7t + 30

- geometry -
**Reiny**, Wednesday, December 7, 2011 at 8:53pmI just solved your question using Calculus, but I am not sure if you know Calculus, so ....

Treat your data two ordered pairs (0,30) and (2,16)

where the first coordinate is time and the second is velocity

slope = (30-16)/(0-2) = -7

so v = -7t + b , using the old y = mx + b format

but (0,30) must satisfy this

30 = 0 + b

b = 30

so v = -7t + 30 , as before

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