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December 26, 2014

December 26, 2014

Posted by **NYSNC** on Wednesday, December 7, 2011 at 3:59pm.

arctanx + arctan(1/x)=∏/2

using calculus theory.

(Hint: Differentiate the left hand side of the identity)

- calculus -
**Anonymous**, Wednesday, December 7, 2011 at 4:16pmActually, since tan(pi/2-x) = cot(x)

and cot = 1/tan it falls right out.

Or, using the sum of tangents formula,

tan(arctanx + arctan(1/x))

= [tan(arctan(x)) + tan(arctan(1/x))][1 - tan(arctan(x))*tan(arctan(1/x))]

= [x + 1/x]/[1 - x*1/x] = (x + 1/x)/0 = oo

tan pi/2 = oo

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