-4 - (1/2) sin theta=-16 +radical 3 over 4
what are the 2 points of intersection?
0<theta<2pi
If you mean
-4 - .5sinθ = -16 + .25√3
then let's multiply by 4 to clear fractions
-16 - 2sinθ = -64 + √3
2sinθ = 48 + √3
Hmmm. not likely
How about
-4 - .5sinθ = (-16 + √3)/4
-16 - 2sinθ = -16 + √3
sinθ = -√3/2
θ = π+π/3 or 2pi-π/3
= 4π/3 or 5π/3
Try using parentheses whenever there's a possible misinterpretation