Posted by MInx on Wednesday, December 7, 2011 at 1:17pm.
You didn't furnish any data.
Sorry, I didnt realize that data didnt attach...here it is..thank you for all your help!
If they are equimolar, then
XCCl4 = 0.5 and
XC6H6 = 0.5
Then partial pressure CCl4 = XCCl4 x PoCCl4 and
partial pressure C6H6 = XC6H6 x PoC6H6
Total P = partial pressure CCl4 + partial pressure C6H6.
XCCl4 in the vapor = PCCl4/total P.
XC6H6 in the vapor = PC6H6/total P.
This will be the composition on condensation.
Substance ∆Gf°
C6H6 (l) 124.50 kJ/mol
C6H6 (g) 129.66 kJ/mol
CCl4 (l) -65.21 kJ/mol
CCl4 (g) -60.59 kJ/mol
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