Posted by MInx on Wednesday, December 7, 2011 at 1:17pm.
Carbon tetrachloride (CCl4) and benzene (C6H6) form ideal solutions. Consider an equimolar solution of CCl4 and C6H6 at 25°C. The vapor above this solutionis collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor.
Chemistry - DrBob222, Wednesday, December 7, 2011 at 2:23pm
You didn't furnish any data.
If they are equimolar, then
XCCl4 = 0.5 and
XC6H6 = 0.5
Then partial pressure CCl4 = XCCl4 x PoCCl4 and
partial pressure C6H6 = XC6H6 x PoC6H6
Total P = partial pressure CCl4 + partial pressure C6H6.
XCCl4 in the vapor = PCCl4/total P.
XC6H6 in the vapor = PC6H6/total P.
This will be the composition on condensation.
Chemistry - Minx, Wednesday, December 7, 2011 at 8:31pm
Sorry, I didn't realize that data didn't attach...here it is..thank you for all your help!
C6H6 (l) 124.50 kJ/mol
C6H6 (g) 129.66 kJ/mol
CCl4 (l) -65.21 kJ/mol
CCl4 (g) -60.59 kJ/mol
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