posted by MInx on .
Carbon tetrachloride (CCl4) and benzene (C6H6) form ideal solutions. Consider an equimolar solution of CCl4 and C6H6 at 25°C. The vapor above this solutionis collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor.
You didn't furnish any data.
If they are equimolar, then
XCCl4 = 0.5 and
XC6H6 = 0.5
Then partial pressure CCl4 = XCCl4 x PoCCl4 and
partial pressure C6H6 = XC6H6 x PoC6H6
Total P = partial pressure CCl4 + partial pressure C6H6.
XCCl4 in the vapor = PCCl4/total P.
XC6H6 in the vapor = PC6H6/total P.
This will be the composition on condensation.
Sorry, I didn't realize that data didn't attach...here it is..thank you for all your help!
C6H6 (l) 124.50 kJ/mol
C6H6 (g) 129.66 kJ/mol
CCl4 (l) -65.21 kJ/mol
CCl4 (g) -60.59 kJ/mol