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October 24, 2014

Posted by **Ruthie** on Wednesday, December 7, 2011 at 12:12pm.

(a+3)/(5a+25)-(a-1)/(3a+15)

(a+3)/5(a+5)-(a-1)/3(a+5)=(a+3)5(a+5)/5(a+5)3(a+5)-(a-1)5(a+5)/5(a+5)3(at5)= 5a^2+25a+15a+75+5a^2+25a-5a-25/5(a+5)3(a+5)

i got (10a^2+60a-50)/5(a+5)3(a+5)and that's wrong. where did i go wrong?

- math -
**Steve**, Wednesday, December 7, 2011 at 12:43pm(a+3)/(5a+25)-(a-1)/(3a+15)

(a+3)/5(a+5)-(a-1)/3(a+5)

=(a+3)**3**(a+5)/5(a+5)3(a+5)-(a-1)5(a+5)/5(a+5)3(a+5)

Aside from that, I'd not include (a+5) twice, making it

=3(a+3)/15(a+5) - 5(a-1)/15(a+5)

= (3a+9-5a+5)/15(a+5)

= 2(7-a)/15(a+5)

- math -
**Reiny**, Wednesday, December 7, 2011 at 12:46pmSince the a+5 is already common, you don't need it twice

LCD = 15(x+5)

so your second line

= 3(a+3)/(15(a+5)) - 5(a-1)/(15(a+5))

= (3a+9 - 5a + 5)/(15(a+5))

= (-2a + 14)/(15(a+5))

=-2(a-7)/(15(a+5))

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