Posted by Ruthie on Wednesday, December 7, 2011 at 12:12pm.
perform indicated operations.
(a+3)/(5a+25)(a1)/(3a+15)
(a+3)/5(a+5)(a1)/3(a+5)=(a+3)5(a+5)/5(a+5)3(a+5)(a1)5(a+5)/5(a+5)3(at5)= 5a^2+25a+15a+75+5a^2+25a5a25/5(a+5)3(a+5)
i got (10a^2+60a50)/5(a+5)3(a+5)and that's wrong. where did i go wrong?

math  Steve, Wednesday, December 7, 2011 at 12:43pm
(a+3)/(5a+25)(a1)/(3a+15)
(a+3)/5(a+5)(a1)/3(a+5)
=(a+3)3(a+5)/5(a+5)3(a+5)(a1)5(a+5)/5(a+5)3(a+5)
Aside from that, I'd not include (a+5) twice, making it
=3(a+3)/15(a+5)  5(a1)/15(a+5)
= (3a+95a+5)/15(a+5)
= 2(7a)/15(a+5)

math  Reiny, Wednesday, December 7, 2011 at 12:46pm
Since the a+5 is already common, you don't need it twice
LCD = 15(x+5)
so your second line
= 3(a+3)/(15(a+5))  5(a1)/(15(a+5))
= (3a+9  5a + 5)/(15(a+5))
= (2a + 14)/(15(a+5))
=2(a7)/(15(a+5))
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