Posted by Lindsay on Wednesday, December 7, 2011 at 9:44am.
I wont show all work, ever. What teacher would ever do that?
balance the equation
Zn+ 2HCl>>ZnCl2 (aq) + H2(g)
so for each mole of acid, you need half that moles of Zn.
moles HCL: Volume*concentraioninMolarity
moles of Zn needed: half of that.
grams of Zn: molesZn*atomicmassZn
Molarity of product? it is a solution of ZincChloride: figure the moles of ZnCl2 made (same moles as Zn), then
molarityZnCl2= molesZnCl2/volume
where volume is still .0164 liters.
This is a regular stoichiometry problem.
Zn + 2HCl ==> ZnCl2 + H2
1. Convert HCl to moles. moles = M x L = ?
2. Use the coefficients in the balanced equation to convert moles HCl to moles Zn.
3. Convert moles Zn to grams. g = moles to molar mass.
b) Convert moles (either Zn or HCl) to moles ZnCl2. Then M = moles/L.
Thank you both for your help! You made it very clear
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