find the distance between points P(7,4) and Q(1,2)to the nearest tenth

d^2 = (-2)^2 + (-6)^2

d^2 = 4 + 36
d^2 = 4 * 10
d = 2 sqrt 10

10, 14 and -8, 14

Find the distance between the line y = -x + 4 and the point P(-1,-1). Round to the nearest tenth.

To find the distance between two points, P(7,4) and Q(1,2), we can use the distance formula. The distance formula is derived from the Pythagorean theorem.

The distance formula is:

d = √((x2 - x1)^2 + (y2 - y1)^2)

Here, (x1, y1) represents the coordinates of point P and (x2, y2) represents the coordinates of point Q.

Let's substitute the given values into the formula:

d = √((1 - 7)^2 + (2 - 4)^2)

First, we simplify the expression within the square root:

d = √((-6)^2 + (-2)^2)

Then, we simplify further:

d = √(36 + 4)

d = √40

Finally, we approximate the square root of 40 to the nearest tenth:

d ≈ 6.3

Therefore, the distance between points P(7,4) and Q(1,2) to the nearest tenth is approximately 6.3 units.