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February 1, 2015

February 1, 2015

Posted by **CyrusDelaney** on Tuesday, December 6, 2011 at 11:02pm.

- calculus -
**Reiny**, Tuesday, December 6, 2011 at 11:56pmln y = ln (1+x)^(1/x)

= (1/x) ln (1+x)

(dy/dx) /y = (-1/x^2)(ln(1+x) + (1/x)(1/(1+x)

dy/dx = y [(-1/x^2) ( ln(1+x) + x/(1+x) ]

or (-1/x^2)( ln(1+x) + x/(1+x) ) (1+x)^(1/x)

pretty messy looking ...

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