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December 18, 2014

December 18, 2014

Posted by **Maria** on Tuesday, December 6, 2011 at 10:55pm.

{ax+b if -1<x<3

{-2 if x ≥3

is continuous on the entire real line

- calculus -
**Reiny**, Tuesday, December 6, 2011 at 11:50pmthe left-side transition point is (-1,2)

so (-1,2) should satisfy y = ax+b

2 = -a + b

the right-side transition point is (3, -2)

so (3,-2) should also satisfy y = ax + b

-2 = 3a + b

subtract those two equations

4a = -4

a = -1

then b = 2+a = 2-1 = 1

a=-1 , b=1

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