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January 29, 2015

January 29, 2015

Posted by **MV** on Tuesday, December 6, 2011 at 10:08pm.

Class is a college level math prep.

Sorry for previous post being incomplete.

I'm thinking:

ln^(x-2)=ln12^(2x+3)

(x-2)ln=(2x+3)ln12

xln-2ln=2xln(12)+3ln(12)

xln-2xln(12)= 2ln+3ln(12)

and not sure

- Algebra 2 -
**Anonymous**, Wednesday, December 7, 2011 at 6:47amYour notation is incorrect.

"2ln" doesn't mean anything

By definition, ln(e^k) = k

so, let's start over:

e^(x-2) = 12^(2x+3)

take ln of both sides:

x-2 = (2x+3) ln 12

x - 2 = 2ln12 x + 3ln12

x(1 - 2ln12) = 2 + 3ln12

x = (2 + 3ln12)/(1 - 2ln12)

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