1.Calculate the energy of a photon whose frequency is 2450 megahertz.
What is the wavelength of waves transmitted by an AM radio station operating at a frequency of 840 kilohertz?
2.
1. Planck's equation applies.
2. the wave equation applies.
for number 1 i got 1.62*10^-24 J
and for number 2 i got 3.5*10^-29 m
but i m not sure if they r right
Answar
To calculate the energy of a photon, you can use the formula:
E = h * f
Where:
E is the energy of the photon
h is Planck's constant (approximately 6.626 x 10^-34 J·s)
f is the frequency of the photon.
In this case, we have the frequency as 2450 megahertz, which is 2450 x 10^6 Hz.
So, plugging in the values into the formula:
E = (6.626 x 10^-34 J·s) * (2450 x 10^6 Hz)
E = 1.621 x 10^-26 J
Therefore, the energy of the photon with a frequency of 2450 megahertz is approximately 1.621 x 10^-26 Joules.
Now, moving on to the second question:
To find the wavelength of waves transmitted by an AM radio station operating at a frequency of 840 kilohertz, you can use the formula:
wavelength = speed of light / frequency
The speed of light is approximately 3 x 10^8 meters per second, and the frequency is 840 x 10^3 Hz.
Plugging in the values into the formula:
wavelength = (3 x 10^8 m/s) / (840 x 10^3 Hz)
wavelength ≈ 357.142 meters
Therefore, the wavelength of waves transmitted by the AM radio station with a frequency of 840 kilohertz is approximately 357.142 meters.