A gas occupies a volume of 0.500L at 125 degrees Celsius and 0.443 atm. What mathematical expression will yield the correct temperature at 0.750 L and 0.689 atm? Is it the combined gas law of P2V1/T1=P2V2/T2?
Yes, that should work although T will be in kelvin. You will then need to convert to C by K = 273+C
Thank you!
Yes, you are correct. The ideal gas law formula for this problem is the combined gas law equation, which states:
P1V1/T1 = P2V2/T2
To find the temperature T2 at the given conditions of 0.750 L and 0.689 atm, you can rearrange the equation and substitute the known values:
T2 = (P2V2 * T1) / (P1V1)
Using the given values:
P1 = 0.443 atm
V1 = 0.500 L
T1 = 125 degrees Celsius (convert to Kelvin by adding 273.15)
P2 = 0.689 atm
V2 = 0.750 L
Substituting the values into the equation:
T2 = (0.689 atm * 0.750 L * (125 + 273.15) K) / (0.443 atm * 0.500 L)
Simplifying the equation will give you the temperature T2 in Kelvin.
Yes, indeed! The mathematical expression you have mentioned, P1V1/T1 = P2V2/T2, is known as the combined gas law. It allows you to solve for an unknown variable, in this case, temperature (T2).
To find the correct temperature at 0.750 L and 0.689 atm, you can use the combined gas law as follows:
P1V1/T1 = P2V2/T2
Substituting the given values:
P1 = 0.443 atm, V1 = 0.500 L, T1 = 125 degrees Celsius (~398 K)
P2 = 0.689 atm, V2 = 0.750 L
We need to find T2; rearrange the equation:
T2 = (P2V2 * T1)/(P1V1)
Now plug in the values:
T2 = (0.689 atm * 0.750 L * 398 K)/(0.443 atm * 0.500 L)
Simplifying this expression will give you the correct temperature at the given conditions.