Solve by substitution.

y=.8x+72
20x+32y=48

How do you get y? i got the x part but i can't seem to get the y part.

solve this:

20x+32 (.8x+72)=48
then, you have x. Then solve y=.8x+72

i actually wrote the second part wrong. Its supposed to be y=.8x+7.2 not 72. and when i solved it i got 10.4 for y and my x is 4.

Is it right?

To solve by substitution, we substitute the value of y from the first equation into the second equation. Let's start solving step by step:

1. Given equations:
y = 0.8x + 72 ----(1)
20x + 32y = 48 ----(2)

2. We solve equation (1) for y:
y = 0.8x + 72 ----(1)

3. Substitute the value of y from equation (1) into equation (2):
20x + 32(0.8x + 72) = 48

4. Distribute the multiplication:
20x + 25.6x + 2304 = 48

5. Combine like terms:
45.6x + 2304 = 48

6. Subtract 2304 from both sides:
45.6x = 48 - 2304
45.6x = -2256

7. Divide both sides by 45.6:
x = -2256 / 45.6
x = -49.47

Now, to find the value of y, substitute the value of x into equation (1):

y = 0.8x + 72
y = 0.8(-49.47) + 72
y = -39.576 + 72
y = 32.424

Therefore, the solution is x = -49.47 and y = 32.424.