Posted by **John** on Tuesday, December 6, 2011 at 7:21pm.

A monatomic ideal gas is compressed adiabatically from a pressure of 1.39 105 Pa and volume of 260 L to a volume of 39.0 L. What is the new pressure of the gas?

- College Physics -
**drwls**, Tuesday, December 6, 2011 at 7:48pm
In an adiabatic compression,

P*V^gamma = constant

where "gamma" is the specific heat ratio, Cp/Cv, which is 5/3 for a monatomic gas.

Therefore,

P2/P1 = [V1/V2)^5/3 = (260/39)^5/3

= 23.62

P2 = 3.28*10^6 Pa

- College Physics -
**John**, Wednesday, December 7, 2011 at 1:13am
Thank you very much

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