A 86.0 kg diver falls from rest into a swimming pool from a height of 6.3 m. It takes 1.44 s for the diver to stop after entering the water. Find the magnitude of the average net force exerted on the diver during that time.

Well, since we're talking about a diver falling into a swimming pool, it sounds like a pretty "diving" situation! But let's get to the problem at hand.

To find the magnitude of the average net force exerted on the diver, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

First, let's find the acceleration of the diver. We can use the equation of motion:

v = u + at,

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

In this case, the diver starts from rest (u = 0) and stops (v = 0) in 1.44 seconds (t = 1.44 s). Therefore, we can rearrange the equation to solve for acceleration:

a = (v - u) / t.

Since the diver stops, the final velocity is 0. So, the equation simplifies to:

a = (0 - 0) / 1.44 s = 0 m/s^2.

Now that we know the acceleration, we can calculate the net force using Newton's second law:

F = m * a.

Plugging in the given mass of the diver (m = 86.0 kg) and the acceleration (a = 0 m/s^2), we get:

F = 86.0 kg * 0 m/s^2 = 0 N.

Wait a minute, that's strange! It seems like the average net force exerted on the diver during that time is actually 0 N. So, it looks like the diver is experiencing no net force during the stopping period.

Maybe it's because the water is doing a great job at cushioning the fall and providing a balanced force on the diver. In any case, no net force means no clownish shenanigans today.

To find the magnitude of the average net force exerted on the diver, we can use Newton's second law of motion, which states that force is equal to the mass of an object multiplied by its acceleration.

1. First, let's find the acceleration of the diver using the kinematic equation relating distance, time, and acceleration. The formula is:

distance = (1/2) * acceleration * time^2

Rearranging the formula to solve for acceleration:

acceleration = (2 * distance) / (time^2)

Plugging in the values:

acceleration = (2 * 6.3 m) / (1.44 s)^2
= 8.203 m/s^2

2. Now that we have the acceleration, we can calculate the net force using Newton's second law.

force = mass * acceleration

Plugging in the values:

force = (86.0 kg) * (8.203 m/s^2)
= 706.158 N

Therefore, the magnitude of the average net force exerted on the diver during that time is approximately 706.158 Newtons.

To find the magnitude of the average net force exerted on the diver, you can use Newton's second law of motion, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration.

First, let's find the acceleration of the diver. We can use the kinematic equation:

vf^2 = vi^2 + 2ad

where vf is the final velocity (which is 0 m/s, since the diver stops), vi is the initial velocity (which is 0 m/s, since the diver falls from rest), a is the acceleration, and d is the distance (which is the height of the fall, 6.3 m).

Plugging in the values, the equation becomes:

0^2 = 0^2 + 2a(6.3)

0 = 12.6a

a = 0 m/s^2

Since the final velocity is 0 m/s and the initial velocity is also 0 m/s, the acceleration turns out to be 0 m/s^2. This means that the diver experiences no acceleration during the time they stop after entering the water.

Now, we can use Newton's second law to find the net force. The equation can be rearranged as:

Fnet = m * a

where Fnet is the net force, m is the mass of the diver (86.0 kg), and a is the acceleration.

Plugging in the values, the equation becomes:

Fnet = 86.0 kg * 0 m/s^2

Fnet = 0 N

Therefore, the magnitude of the average net force exerted on the diver is 0 N.

Vf^2 = Vo^2 + 2g*d,

Vf^2 = 0 + 19.6*6.3 = 123.48,
Vf = 11.1 m/s.

a = (Vf - Vo) / t,
a = (0 - 11.1) / 1.44 = - 7.72 m/s^2.

Fn = ma = 86 * (-7.72) = -664 N. in
opposite direction.