Posted by **Bob** on Tuesday, December 6, 2011 at 5:09pm.

A 86.0 kg diver falls from rest into a swimming pool from a height of 6.3 m. It takes 1.44 s for the diver to stop after entering the water. Find the magnitude of the average net force exerted on the diver during that time.

- Physics -
**Henry**, Thursday, December 8, 2011 at 7:47pm
Vf^2 = Vo^2 + 2g*d,

Vf^2 = 0 + 19.6*6.3 = 123.48,

Vf = 11.1 m/s.

a = (Vf - Vo) / t,

a = (0 - 11.1) / 1.44 = - 7.72 m/s^2.

Fn = ma = 86 * (-7.72) = -664 N. in

opposite direction.

## Answer This Question

## Related Questions

- physics - A 62.0 kg diver falls from rest into a swimming pool from a height of ...
- physics - A 62.0 kg diver falls from rest into a swimming pool from a height of...
- Physics please help!! - A 86.0 kg diver falls from rest into a swimming pool ...
- physics again... - A 62.0 kg diver falls from rest into a swimming pool from a ...
- Physics - At the local swimming pool, the diving board is elevated h = 7.5 m ...
- physics - A diver jumps from a height of 24.0m into a swimming pool. What's her ...
- PHYSICS - A 58.3 kg diver steps o a diving board and drops straight down into ...
- physics - A 42.1 kg diver steps off a diving board and drops straight down into ...
- physics- energy and work - A 47.6-kg diver steps off a 10.82 m high diving board...
- physics - A 65 kg diver jumps off of a 10.0 m tower. a. Find the diver's ...

More Related Questions