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April 18, 2014

April 18, 2014

Posted by **sand** on Tuesday, December 6, 2011 at 5:45am.

- physics -
**drwls**, Tuesday, December 6, 2011 at 6:27amF(min)/A = 4.0*10^8 N/m^2

A = 6*(0.0556)*(0.005) m^2

= 1.668*10^-3 m^2

is the load-bearing area.

Solve for F(min)

- physics -
**sand**, Tuesday, December 6, 2011 at 8:04amThanks a lot

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