Algebra
posted by MV on .
e^x212^2x+3=0

You have a 2 and a +3 in that equation. Why don't you combine them? Or is (x2) supposed to be an exponent of e?
If you are only studying algebra, I am surprised that they are teaching you to use e = 2.71828...
You should use parentheses to clarify what the exponents are in your equation.
In any case, it appears to be a transcendental equation that will have to be solved by graphing or iteration. 
e^(x2)12^(2x+3)=0
Class is a college level math prep.
Sorry for being incomplete in the post.