calculus
posted by saud on .
find the are of the surface of the part of the sphere (x^2)+(y^2)+(z^2)=4 that lies above the plane z=4

Something fishy here.
the sphere has centre at (0,0,0) and radius 2
so it won't even reach the plane given by z=4
I guess we could say the surface area which lies above z=4 would be zero.