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January 29, 2015

January 29, 2015

Posted by **Anonymous** on Monday, December 5, 2011 at 9:40pm.

i know that x^2+6x+9=2x^2+5x+3

and

6=x^2-x

(i forgot basic algebra)

- geometry -
**Reiny**, Monday, December 5, 2011 at 10:15pmthen (x+3)/(x+1) = (2x+3)/(x+3)

crossmultiply

2x^2 + 5x + 3 = x^2 + 6x + 9

x^2 - x - 6 = 0

(x-3)(x+2) = 0

x = 3 or x = -2

if x = 3, the 3 terms are 4, 6, and 9

(note 6/4 = 9/6)

if x = -2, the 3 terms are 0, 1, and -1

but that is not possible, if the first term of a geometric sequence is zero, all the remaining terms would be zero.

so x = 3

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