Posted by math whizz on Monday, December 5, 2011 at 9:12pm.
dy/dx=ksqrt(t)
dy=ksqrt(t)dt
Integrate both sides:
y=k(2/3)t^(3/2) + C
where C is an integration constant determined from initial conditions.
Thus
y = (2k/3)t^(3/2) + C
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