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November 26, 2014

November 26, 2014

Posted by **-Untamed-** on Monday, December 5, 2011 at 8:08pm.

Find the equation of the function in standard form.

Rewrite the equation in general form.

Could someone explain to me how to do this, just don't understand.

- Math -
**MathMate**, Monday, December 5, 2011 at 9:00pmThe canonical form of a quadratic equation is:

y=a(x-h)²+k

where

a is a constant

(h,k) is the vertex.

So in the given case, h=3, k=-4, and a remains to be found.

We can find a since we know the curves passes through (4,1), hence

1=a(4-3)²-4

1=a-4

solve for a to get

a=5

Check:

y=5(x-3)²-4

For x=4, y=5(1)²-4=1, OK

For the general form, expand the equation

y=5(x-3)²-4

y=5x²-30x+41

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