Posted by laura on Monday, December 5, 2011 at 6:48pm.
First determine which is the limiting reagent.
moles C3H8 = 1g/molar mass = about 0.02 but you need to do it more accurately.
moles O2 = 1g/molar mass = about 0.02.
Now convert moles C3H8 to moles CO2. I have about 0.06.
Convert moles O2 to moles CO2. I have about 0.02.
Both answers can't be correct; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent providing that value is the limiting reagent. Therefore, O2 is the limiting reagent.
Since all of that will be consumed, you should convert moles O2 to moles C3H8 to determine moles C3H8 consumed, then subtract from initial moles to determine how much C3H8 remains unreacted. Add moles C3H8 + moles CO2 + moles H2O and use PV = nRT to solve for final P.
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