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April 16, 2014

April 16, 2014

Posted by **Caleb** on Monday, December 5, 2011 at 6:26pm.

- Math (Calculus) -
**bobpursley**, Monday, December 5, 2011 at 6:39pmf= ln u

u= tan x

f'= 1/u *u'

u'= sec^2x x'

so

g'(x)=1/3PI * 1/tanx * sec^2 x checkall this.

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