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June 30, 2015

June 30, 2015

Posted by **Anonymous** on Monday, December 5, 2011 at 6:23pm.

(implicit differentiation)

- Calc -
**drwls**, Monday, December 5, 2011 at 6:34pmDifferentiate both sides with respect to x, with y considered a function of x.

(2/3)/x^1/3 + [(2/3)/y^1/3] dy/dx = 0

dy/dx = -[y/x]^1/3

Then do it again.

d^2/dx^2 = .......