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find d^2y/dx^2 of x^2/3 + y^2/3 =1
(implicit differentiation)

  • Calc - ,

    Differentiate both sides with respect to x, with y considered a function of x.

    (2/3)/x^1/3 + [(2/3)/y^1/3] dy/dx = 0
    dy/dx = -[y/x]^1/3

    Then do it again.

    d^2/dx^2 = .......

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