Posted by Anonymous on Monday, December 5, 2011 at 6:23pm.
Differentiate both sides with respect to x, with y considered a function of x. (2/3)/x^1/3 + [(2/3)/y^1/3] dy/dx = 0 dy/dx = -[y/x]^1/3 Then do it again. d^2/dx^2 = .......