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November 28, 2014

November 28, 2014

Posted by **ann** on Monday, December 5, 2011 at 6:09pm.

log with base 3

i cant figure it out

- calculus -
**bobpursley**, Monday, December 5, 2011 at 6:16pmf= log3(u)

f'= 1/u * log3 e * u'

so here

f'=1/(x+x^2) * log3 e * (1+2x)

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