Posted by ann on .
what is the derivative of log3(x+X^2)
log with base 3
i cant figure it out

calculus 
bobpursley,
f= log3(u)
f'= 1/u * log3 e * u'
so here
f'=1/(x+x^2) * log3 e * (1+2x)
Posted by ann on .
what is the derivative of log3(x+X^2)
log with base 3
i cant figure it out
f= log3(u)
f'= 1/u * log3 e * u'
so here
f'=1/(x+x^2) * log3 e * (1+2x)