trig
posted by Anonymous .
find all solutions of 2sinx=1cosx in the interval from 0 to 360

square both sides.
4sin^2= 12cos+cos^2
4(1cos^2)=12cos+cos^2
now, gather terms, it is a quadratic, solve using the quadratic equation. 
okay so i got (3/5) and 1, i am supposed to find the solutions in the interval from 0degrees to 360degrees

the previous ans. is wrong as if we sq. the eqn. it generates false solutions a better method is to divide coefficients of sin and cos by root of sq. of coeff.ofsin+sq. of coeff of cos . that is main pt. remaining we will proceed by making it an argument in cos . and then make general sol. and find no. of sol. or diff solutions by putting value of n in general solution

the previous ans. is wrong as if we sq. the eqn. it generates false solutions a better method is to divide coefficients of sin and cos by root of( sq. of coeff.ofsin+sq. of coeff of cos) . that is main pt. remaining we will proceed by making it an argument in cos . and then make general sol. and find no. of sol. or diff solutions by putting value of n in general solution