Posted by -Untamed- on Monday, December 5, 2011 at 5:27pm.
x^3 + 8x^2 = 20x
How do I find the root of ^ that equation?
2x^2-10x+12 = 0
^ I found that one by...
x-3 = 0
x = 3
x-2 = 0
^ Is that the correct way to solve for that one?
- Math - MathMate, Monday, December 5, 2011 at 6:17pm
Your solution to the second equation is correct, and the procedure also.
For the first equation, think of it as:
x^3 + 8x^2 = 20x
x^3 + 8x^2 - 20x = 0
x(x^2 + 8x - 20) = 0
then x=0 is a solution, and you can get two more solutions from the part in parentheses in a similar way to the second equation.
- Math - -Untamed-, Monday, December 5, 2011 at 6:26pm
Thanks so much MathMate =)
- Math - MathMate, Monday, December 5, 2011 at 6:56pm
You're welcome, and keep up the good work!
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