Posted by **-Untamed-** on Monday, December 5, 2011 at 5:27pm.

x^3 + 8x^2 = 20x

How do I find the root of ^ that equation?

2x^2-10x+12 = 0

^ I found that one by...

2(x-3)(x-2)

x-3 = 0

x = 3

x-2 = 0

x =2

^ Is that the correct way to solve for that one?

- Math -
**MathMate**, Monday, December 5, 2011 at 6:17pm
Your solution to the second equation is correct, and the procedure also.

For the first equation, think of it as:

x^3 + 8x^2 = 20x

x^3 + 8x^2 - 20x = 0

x(x^2 + 8x - 20) = 0

then x=0 is a solution, and you can get two more solutions from the part in parentheses in a similar way to the second equation.

- Math -
**-Untamed-**, Monday, December 5, 2011 at 6:26pm
Thanks so much MathMate =)

- Math -
**MathMate**, Monday, December 5, 2011 at 6:56pm
You're welcome, and keep up the good work!

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