Posted by Untamed on .
x^3 + 8x^2 = 20x
How do I find the root of ^ that equation?
2x^210x+12 = 0
^ I found that one by...
2(x3)(x2)
x3 = 0
x = 3
x2 = 0
x =2
^ Is that the correct way to solve for that one?

Math 
MathMate,
Your solution to the second equation is correct, and the procedure also.
For the first equation, think of it as:
x^3 + 8x^2 = 20x
x^3 + 8x^2  20x = 0
x(x^2 + 8x  20) = 0
then x=0 is a solution, and you can get two more solutions from the part in parentheses in a similar way to the second equation. 
Math 
Untamed,
Thanks so much MathMate =)

Math 
MathMate,
You're welcome, and keep up the good work!